1/3y^2+y+1/12=0

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Solution for 1/3y^2+y+1/12=0 equation: 


y in (-oo:+oo)

(1/3)*y^2+y+1/12 = 0

1/3*y^2+y+1/12 = 0

DELTA = 1^2-(1/12*1/3*4)

DELTA = 8/9

DELTA > 0

y = ((8/9)^(1/2)-1)/(1/3*2) or y = (-(8/9)^(1/2)-1)/(1/3*2)

y = 3/2*((8/9)^(1/2)-1) or y = -3/2*((8/9)^(1/2)+1)

y in { -3/2*((8/9)^(1/2)+1), 3/2*((8/9)^(1/2)-1) }

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